8(x^2+2x+1)+25=0

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Solution for 8(x^2+2x+1)+25=0 equation:


Simplifying
8(x2 + 2x + 1) + 25 = 0

Reorder the terms:
8(1 + 2x + x2) + 25 = 0
(1 * 8 + 2x * 8 + x2 * 8) + 25 = 0
(8 + 16x + 8x2) + 25 = 0

Reorder the terms:
8 + 25 + 16x + 8x2 = 0

Combine like terms: 8 + 25 = 33
33 + 16x + 8x2 = 0

Solving
33 + 16x + 8x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
8 the coefficient of the squared term: 

Divide each side by '8'.
4.125 + 2x + x2 = 0

Move the constant term to the right:

Add '-4.125' to each side of the equation.
4.125 + 2x + -4.125 + x2 = 0 + -4.125

Reorder the terms:
4.125 + -4.125 + 2x + x2 = 0 + -4.125

Combine like terms: 4.125 + -4.125 = 0.000
0.000 + 2x + x2 = 0 + -4.125
2x + x2 = 0 + -4.125

Combine like terms: 0 + -4.125 = -4.125
2x + x2 = -4.125

The x term is 2x.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2x + 1 + x2 = -4.125 + 1

Reorder the terms:
1 + 2x + x2 = -4.125 + 1

Combine like terms: -4.125 + 1 = -3.125
1 + 2x + x2 = -3.125

Factor a perfect square on the left side:
(x + 1)(x + 1) = -3.125

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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